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5(x-1)=8+2(x-1)
We move all terms to the left:
5(x-1)-(8+2(x-1))=0
We multiply parentheses
5x-(8+2(x-1))-5=0
We calculate terms in parentheses: -(8+2(x-1)), so:We get rid of parentheses
8+2(x-1)
determiningTheFunctionDomain 2(x-1)+8
We multiply parentheses
2x-2+8
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
5x-2x-6-5=0
We add all the numbers together, and all the variables
3x-11=0
We move all terms containing x to the left, all other terms to the right
3x=11
x=11/3
x=3+2/3
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