5(x-1)+6(x+2)=9(x+3)

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Solution for 5(x-1)+6(x+2)=9(x+3) equation: 



5(x-1)+6(x+2)=9(x+3)

We move all terms to the left:

5(x-1)+6(x+2)-(9(x+3))=0

We multiply parentheses

5x+6x-(9(x+3))-5+12=0



We calculate terms in parentheses: -(9(x+3)), so:

9(x+3)

We multiply parentheses

9x+27

Back to the equation:

-(9x+27)



We add all the numbers together, and all the variables

11x-(9x+27)+7=0

We get rid of parentheses

11x-9x-27+7=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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