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5(x-1)+4=3x+2(1+x)
We move all terms to the left:
5(x-1)+4-(3x+2(1+x))=0
We add all the numbers together, and all the variables
5(x-1)-(3x+2(x+1))+4=0
We multiply parentheses
5x-(3x+2(x+1))-5+4=0
We calculate terms in parentheses: -(3x+2(x+1)), so:We add all the numbers together, and all the variables
3x+2(x+1)
We multiply parentheses
3x+2x+2
We add all the numbers together, and all the variables
5x+2
Back to the equation:
-(5x+2)
5x-(5x+2)-1=0
We get rid of parentheses
5x-5x-2-1=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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