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5(x-1)+3(2x+9)-2=4(3+-1)+2(4x+3)
We move all terms to the left:
5(x-1)+3(2x+9)-2-(4(3+-1)+2(4x+3))=0
We add all the numbers together, and all the variables
5(x-1)+3(2x+9)-(42+2(4x+3))-2=0
We multiply parentheses
5x+6x-(42+2(4x+3))-5+27-2=0
We calculate terms in parentheses: -(42+2(4x+3)), so:We add all the numbers together, and all the variables
42+2(4x+3)
determiningTheFunctionDomain 2(4x+3)+42
We multiply parentheses
8x+6+42
We add all the numbers together, and all the variables
8x+48
Back to the equation:
-(8x+48)
11x-(8x+48)+20=0
We get rid of parentheses
11x-8x-48+20=0
We add all the numbers together, and all the variables
3x-28=0
We move all terms containing x to the left, all other terms to the right
3x=28
x=28/3
x=9+1/3
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