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5(x-1)+1=2(x-2)
We move all terms to the left:
5(x-1)+1-(2(x-2))=0
We multiply parentheses
5x-(2(x-2))-5+1=0
We calculate terms in parentheses: -(2(x-2)), so:We add all the numbers together, and all the variables
2(x-2)
We multiply parentheses
2x-4
Back to the equation:
-(2x-4)
5x-(2x-4)-4=0
We get rid of parentheses
5x-2x+4-4=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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