5(x+8)-7x=-(2x-4)5x-20=3(x-4)

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Solution for 5(x+8)-7x=-(2x-4)5x-20=3(x-4) equation: 



5(x+8)-7x=-(2x-4)5x-20=3(x-4)

We move all terms to the left:

5(x+8)-7x-(-(2x-4)5x-20)=0

We add all the numbers together, and all the variables

-7x+5(x+8)-(-(2x-4)5x-20)=0

We multiply parentheses

-7x+5x-(-(2x-4)5x-20)+40=0



We calculate terms in parentheses: -(-(2x-4)5x-20), so:

-(2x-4)5x-20

We multiply parentheses

-10x^2+20x-20

Back to the equation:

-(-10x^2+20x-20)



We add all the numbers together, and all the variables

-(-10x^2+20x-20)-2x+40=0

We get rid of parentheses

10x^2-20x-2x+20+40=0

We add all the numbers together, and all the variables

10x^2-22x+60=0

a = 10; b = -22; c = +60;
Δ = b2-4ac
Δ = -222-4·10·60
Δ = -1916
Delta is less than zero, so there is no solution for the equation

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