5(x+5)+3=-10(x-5)-2

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Solution for 5(x+5)+3=-10(x-5)-2 equation: 



5(x+5)+3=-10(x-5)-2

We move all terms to the left:

5(x+5)+3-(-10(x-5)-2)=0

We multiply parentheses

5x-(-10(x-5)-2)+25+3=0



We calculate terms in parentheses: -(-10(x-5)-2), so:

-10(x-5)-2

We multiply parentheses

-10x+50-2

We add all the numbers together, and all the variables

-10x+48

Back to the equation:

-(-10x+48)



We add all the numbers together, and all the variables

5x-(-10x+48)+28=0

We get rid of parentheses

5x+10x-48+28=0

We add all the numbers together, and all the variables

15x-20=0

We move all terms containing x to the left, all other terms to the right

15x=20

x=20/15

x=1+1/3

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