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5(x+4)=5(x-3)
We move all terms to the left:
5(x+4)-(5(x-3))=0
We multiply parentheses
5x-(5(x-3))+20=0
We calculate terms in parentheses: -(5(x-3)), so:We get rid of parentheses
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
5x-5x+15+20=0
We add all the numbers together, and all the variables
35!=0
There is no solution for this equation
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