5(x+4)=-7(x-2)

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Solution for 5(x+4)=-7(x-2) equation:



5(x+4)=-7(x-2)
We move all terms to the left:
5(x+4)-(-7(x-2))=0
We multiply parentheses
5x-(-7(x-2))+20=0
We calculate terms in parentheses: -(-7(x-2)), so:
-7(x-2)
We multiply parentheses
-7x+14
Back to the equation:
-(-7x+14)
We get rid of parentheses
5x+7x-14+20=0
We add all the numbers together, and all the variables
12x+6=0
We move all terms containing x to the left, all other terms to the right
12x=-6
x=-6/12
x=-1/2

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