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5(x+4)-7=2x+3(5+x)
We move all terms to the left:
5(x+4)-7-(2x+3(5+x))=0
We add all the numbers together, and all the variables
5(x+4)-(2x+3(x+5))-7=0
We multiply parentheses
5x-(2x+3(x+5))+20-7=0
We calculate terms in parentheses: -(2x+3(x+5)), so:We add all the numbers together, and all the variables
2x+3(x+5)
We multiply parentheses
2x+3x+15
We add all the numbers together, and all the variables
5x+15
Back to the equation:
-(5x+15)
5x-(5x+15)+13=0
We get rid of parentheses
5x-5x-15+13=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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