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5(x+4)-2=30-3(x-4)
We move all terms to the left:
5(x+4)-2-(30-3(x-4))=0
We multiply parentheses
5x-(30-3(x-4))+20-2=0
We calculate terms in parentheses: -(30-3(x-4)), so:We add all the numbers together, and all the variables
30-3(x-4)
determiningTheFunctionDomain -3(x-4)+30
We multiply parentheses
-3x+12+30
We add all the numbers together, and all the variables
-3x+42
Back to the equation:
-(-3x+42)
5x-(-3x+42)+18=0
We get rid of parentheses
5x+3x-42+18=0
We add all the numbers together, and all the variables
8x-24=0
We move all terms containing x to the left, all other terms to the right
8x=24
x=24/8
x=3
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