5(x+4)+7=10x-5(x-4)

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Solution for 5(x+4)+7=10x-5(x-4) equation: 



5(x+4)+7=10x-5(x-4)

We move all terms to the left:

5(x+4)+7-(10x-5(x-4))=0

We multiply parentheses

5x-(10x-5(x-4))+20+7=0



We calculate terms in parentheses: -(10x-5(x-4)), so:

10x-5(x-4)

We multiply parentheses

10x-5x+20

We add all the numbers together, and all the variables

5x+20

Back to the equation:

-(5x+20)



We add all the numbers together, and all the variables

5x-(5x+20)+27=0

We get rid of parentheses

5x-5x-20+27=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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