5(x+4)+20=5-4(x-2)

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Solution for 5(x+4)+20=5-4(x-2) equation: 



5(x+4)+20=5-4(x-2)

We move all terms to the left:

5(x+4)+20-(5-4(x-2))=0

We multiply parentheses

5x-(5-4(x-2))+20+20=0



We calculate terms in parentheses: -(5-4(x-2)), so:

5-4(x-2)

determiningTheFunctionDomain
-4(x-2)+5

We multiply parentheses

-4x+8+5

We add all the numbers together, and all the variables

-4x+13

Back to the equation:

-(-4x+13)



We add all the numbers together, and all the variables

5x-(-4x+13)+40=0

We get rid of parentheses

5x+4x-13+40=0

We add all the numbers together, and all the variables

9x+27=0

We move all terms containing x to the left, all other terms to the right

9x=-27

x=-27/9

x=-3

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