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5(x+4)(x+4)=60
We move all terms to the left:
5(x+4)(x+4)-(60)=0
We multiply parentheses ..
5(+x^2+4x+4x+16)-60=0
We multiply parentheses
5x^2+20x+20x+80-60=0
We add all the numbers together, and all the variables
5x^2+40x+20=0
a = 5; b = 40; c = +20;
Δ = b2-4ac
Δ = 402-4·5·20
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-20\sqrt{3}}{2*5}=\frac{-40-20\sqrt{3}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+20\sqrt{3}}{2*5}=\frac{-40+20\sqrt{3}}{10} $
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