5(x+3)=4x+21

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Solution for 5(x+3)=4x+21 equation: 



5(x+3)=4x+21

We move all terms to the left:

5(x+3)-(4x+21)=0

We multiply parentheses

5x-(4x+21)+15=0

We get rid of parentheses

5x-4x-21+15=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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