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5(x+3)=2(2x-3)
We move all terms to the left:
5(x+3)-(2(2x-3))=0
We multiply parentheses
5x-(2(2x-3))+15=0
We calculate terms in parentheses: -(2(2x-3)), so:We get rid of parentheses
2(2x-3)
We multiply parentheses
4x-6
Back to the equation:
-(4x-6)
5x-4x+6+15=0
We add all the numbers together, and all the variables
x+21=0
We move all terms containing x to the left, all other terms to the right
x=-21
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