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5(x+3)=2(10x-1)-4(2x+6)
We move all terms to the left:
5(x+3)-(2(10x-1)-4(2x+6))=0
We multiply parentheses
5x-(2(10x-1)-4(2x+6))+15=0
We calculate terms in parentheses: -(2(10x-1)-4(2x+6)), so:We get rid of parentheses
2(10x-1)-4(2x+6)
We multiply parentheses
20x-8x-2-24
We add all the numbers together, and all the variables
12x-26
Back to the equation:
-(12x-26)
5x-12x+26+15=0
We add all the numbers together, and all the variables
-7x+41=0
We move all terms containing x to the left, all other terms to the right
-7x=-41
x=-41/-7
x=5+6/7
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