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5(x+3)=10(2x-1)
We move all terms to the left:
5(x+3)-(10(2x-1))=0
We multiply parentheses
5x-(10(2x-1))+15=0
We calculate terms in parentheses: -(10(2x-1)), so:We get rid of parentheses
10(2x-1)
We multiply parentheses
20x-10
Back to the equation:
-(20x-10)
5x-20x+10+15=0
We add all the numbers together, and all the variables
-15x+25=0
We move all terms containing x to the left, all other terms to the right
-15x=-25
x=-25/-15
x=1+2/3
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