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5(x+3)-7=2x+3(4+x)
We move all terms to the left:
5(x+3)-7-(2x+3(4+x))=0
We add all the numbers together, and all the variables
5(x+3)-(2x+3(x+4))-7=0
We multiply parentheses
5x-(2x+3(x+4))+15-7=0
We calculate terms in parentheses: -(2x+3(x+4)), so:We add all the numbers together, and all the variables
2x+3(x+4)
We multiply parentheses
2x+3x+12
We add all the numbers together, and all the variables
5x+12
Back to the equation:
-(5x+12)
5x-(5x+12)+8=0
We get rid of parentheses
5x-5x-12+8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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