5(x+3)-3(x-1)=2(x+1)

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Solution for 5(x+3)-3(x-1)=2(x+1) equation:


Simplifying
5(x + 3) + -3(x + -1) = 2(x + 1)

Reorder the terms:
5(3 + x) + -3(x + -1) = 2(x + 1)
(3 * 5 + x * 5) + -3(x + -1) = 2(x + 1)
(15 + 5x) + -3(x + -1) = 2(x + 1)

Reorder the terms:
15 + 5x + -3(-1 + x) = 2(x + 1)
15 + 5x + (-1 * -3 + x * -3) = 2(x + 1)
15 + 5x + (3 + -3x) = 2(x + 1)

Reorder the terms:
15 + 3 + 5x + -3x = 2(x + 1)

Combine like terms: 15 + 3 = 18
18 + 5x + -3x = 2(x + 1)

Combine like terms: 5x + -3x = 2x
18 + 2x = 2(x + 1)

Reorder the terms:
18 + 2x = 2(1 + x)
18 + 2x = (1 * 2 + x * 2)
18 + 2x = (2 + 2x)

Add '-2x' to each side of the equation.
18 + 2x + -2x = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0
18 + 0 = 2 + 2x + -2x
18 = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0
18 = 2 + 0
18 = 2

Solving
18 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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