5(x+3)-10=5-2(x-7)+3x

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Solution for 5(x+3)-10=5-2(x-7)+3x equation: 



5(x+3)-10=5-2(x-7)+3x

We move all terms to the left:

5(x+3)-10-(5-2(x-7)+3x)=0

We multiply parentheses

5x-(5-2(x-7)+3x)+15-10=0



We calculate terms in parentheses: -(5-2(x-7)+3x), so:

5-2(x-7)+3x

determiningTheFunctionDomain
-2(x-7)+3x+5

We add all the numbers together, and all the variables

3x-2(x-7)+5

We multiply parentheses

3x-2x+14+5

We add all the numbers together, and all the variables

x+19

Back to the equation:

-(x+19)



We add all the numbers together, and all the variables

5x-(x+19)+5=0

We get rid of parentheses

5x-x-19+5=0

We add all the numbers together, and all the variables

4x-14=0

We move all terms containing x to the left, all other terms to the right

4x=14

x=14/4

x=3+1/2

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