5(x+3)+x=4(x+3)+2

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Solution for 5(x+3)+x=4(x+3)+2 equation: 



5(x+3)+x=4(x+3)+2

We move all terms to the left:

5(x+3)+x-(4(x+3)+2)=0

We add all the numbers together, and all the variables

x+5(x+3)-(4(x+3)+2)=0

We multiply parentheses

x+5x-(4(x+3)+2)+15=0



We calculate terms in parentheses: -(4(x+3)+2), so:

4(x+3)+2

We multiply parentheses

4x+12+2

We add all the numbers together, and all the variables

4x+14

Back to the equation:

-(4x+14)



We add all the numbers together, and all the variables

6x-(4x+14)+15=0

We get rid of parentheses

6x-4x-14+15=0

We add all the numbers together, and all the variables

2x+1=0

We move all terms containing x to the left, all other terms to the right

2x=-1

x=-1/2

x=-1/2

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