5(x+3)+4=3(x+2)+15

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Solution for 5(x+3)+4=3(x+2)+15 equation: 



5(x+3)+4=3(x+2)+15

We move all terms to the left:

5(x+3)+4-(3(x+2)+15)=0

We multiply parentheses

5x-(3(x+2)+15)+15+4=0



We calculate terms in parentheses: -(3(x+2)+15), so:

3(x+2)+15

We multiply parentheses

3x+6+15

We add all the numbers together, and all the variables

3x+21

Back to the equation:

-(3x+21)



We add all the numbers together, and all the variables

5x-(3x+21)+19=0

We get rid of parentheses

5x-3x-21+19=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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