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5(x+3)+4(x-1)=7(x+3)
We move all terms to the left:
5(x+3)+4(x-1)-(7(x+3))=0
We multiply parentheses
5x+4x-(7(x+3))+15-4=0
We calculate terms in parentheses: -(7(x+3)), so:We add all the numbers together, and all the variables
7(x+3)
We multiply parentheses
7x+21
Back to the equation:
-(7x+21)
9x-(7x+21)+11=0
We get rid of parentheses
9x-7x-21+11=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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