5(x+3)+3(x-2)=41

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Solution for 5(x+3)+3(x-2)=41 equation: 



5(x+3)+3(x-2)=41

We move all terms to the left:

5(x+3)+3(x-2)-(41)=0

We multiply parentheses

5x+3x+15-6-41=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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