5(x+3)(x+1)=0

Solution for 5(x+3)(x+1)=0 equation:

5(x+3)(x+1)=0

We multiply parentheses ..

5(+x^2+x+3x+3)=0

We multiply parentheses

5x^2+5x+15x+15=0

We add all the numbers together, and all the variables

5x^2+20x+15=0

a = 5; b = 20; c = +15;
Δ = b2-4ac
Δ = 202-4·5·15
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10}{2*5}=\frac{-30}{10}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10}{2*5}=\frac{-10}{10}
=-1
$