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5(x+3)(4+x)=0
We add all the numbers together, and all the variables
5(x+3)(x+4)=0
We multiply parentheses ..
5(+x^2+4x+3x+12)=0
We multiply parentheses
5x^2+20x+15x+60=0
We add all the numbers together, and all the variables
5x^2+35x+60=0
a = 5; b = 35; c = +60;
Δ = b2-4ac
Δ = 352-4·5·60
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5}{2*5}=\frac{-40}{10} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5}{2*5}=\frac{-30}{10} =-3 $
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