5(x+20)+4(4x+2)=108

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Solution for 5(x+20)+4(4x+2)=108 equation: 



5(x+20)+4(4x+2)=108

We move all terms to the left:

5(x+20)+4(4x+2)-(108)=0

We multiply parentheses

5x+16x+100+8-108=0

We add all the numbers together, and all the variables

21x=0

x=0/21

x=0

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