5(x+2)=6x-2(x-3)

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Solution for 5(x+2)=6x-2(x-3) equation: 



5(x+2)=6x-2(x-3)

We move all terms to the left:

5(x+2)-(6x-2(x-3))=0

We multiply parentheses

5x-(6x-2(x-3))+10=0



We calculate terms in parentheses: -(6x-2(x-3)), so:

6x-2(x-3)

We multiply parentheses

6x-2x+6

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

5x-4x-6+10=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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