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5(x+2)=3x+2(x+5)
We move all terms to the left:
5(x+2)-(3x+2(x+5))=0
We multiply parentheses
5x-(3x+2(x+5))+10=0
We calculate terms in parentheses: -(3x+2(x+5)), so:We get rid of parentheses
3x+2(x+5)
We multiply parentheses
3x+2x+10
We add all the numbers together, and all the variables
5x+10
Back to the equation:
-(5x+10)
5x-5x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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