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5(x+2)=3-(x+8)
We move all terms to the left:
5(x+2)-(3-(x+8))=0
We multiply parentheses
5x-(3-(x+8))+10=0
We calculate terms in parentheses: -(3-(x+8)), so:We get rid of parentheses
3-(x+8)
determiningTheFunctionDomain -(x+8)+3
We get rid of parentheses
-x-8+3
We add all the numbers together, and all the variables
-1x-5
Back to the equation:
-(-1x-5)
5x+1x+5+10=0
We add all the numbers together, and all the variables
6x+15=0
We move all terms containing x to the left, all other terms to the right
6x=-15
x=-15/6
x=-2+1/2
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