5(x+2)=3(x-5)=29

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Solution for 5(x+2)=3(x-5)=29 equation: 



5(x+2)=3(x-5)=29

We move all terms to the left:

5(x+2)-(3(x-5))=0

We multiply parentheses

5x-(3(x-5))+10=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We get rid of parentheses

5x-3x+15+10=0

We add all the numbers together, and all the variables

2x+25=0

We move all terms containing x to the left, all other terms to the right

2x=-25

x=-25/2

x=-12+1/2

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