5(x+2)=2+3(x+4)-4

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Solution for 5(x+2)=2+3(x+4)-4 equation: 



5(x+2)=2+3(x+4)-4

We move all terms to the left:

5(x+2)-(2+3(x+4)-4)=0

We multiply parentheses

5x-(2+3(x+4)-4)+10=0



We calculate terms in parentheses: -(2+3(x+4)-4), so:

2+3(x+4)-4

determiningTheFunctionDomain
3(x+4)+2-4

We add all the numbers together, and all the variables

3(x+4)-2

We multiply parentheses

3x+12-2

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We get rid of parentheses

5x-3x-10+10=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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