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5(x+2)8x=-8
We move all terms to the left:
5(x+2)8x-(-8)=0
We add all the numbers together, and all the variables
5(x+2)8x+8=0
We multiply parentheses
40x^2+80x+8=0
a = 40; b = 80; c = +8;
Δ = b2-4ac
Δ = 802-4·40·8
Δ = 5120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5120}=\sqrt{1024*5}=\sqrt{1024}*\sqrt{5}=32\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-32\sqrt{5}}{2*40}=\frac{-80-32\sqrt{5}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+32\sqrt{5}}{2*40}=\frac{-80+32\sqrt{5}}{80} $
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