5(x+2)-6=-6-(3x+12)

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Solution for 5(x+2)-6=-6-(3x+12) equation: 



5(x+2)-6=-6-(3x+12)

We move all terms to the left:

5(x+2)-6-(-6-(3x+12))=0

We multiply parentheses

5x-(-6-(3x+12))+10-6=0



We calculate terms in parentheses: -(-6-(3x+12)), so:

-6-(3x+12)

determiningTheFunctionDomain
-(3x+12)-6

We get rid of parentheses

-3x-12-6

We add all the numbers together, and all the variables

-3x-18

Back to the equation:

-(-3x-18)



We add all the numbers together, and all the variables

5x-(-3x-18)+4=0

We get rid of parentheses

5x+3x+18+4=0

We add all the numbers together, and all the variables

8x+22=0

We move all terms containing x to the left, all other terms to the right

8x=-22

x=-22/8

x=-2+3/4

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