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5(x+2)-3x=2(x+4)
We move all terms to the left:
5(x+2)-3x-(2(x+4))=0
We add all the numbers together, and all the variables
-3x+5(x+2)-(2(x+4))=0
We multiply parentheses
-3x+5x-(2(x+4))+10=0
We calculate terms in parentheses: -(2(x+4)), so:We add all the numbers together, and all the variables
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
2x-(2x+8)+10=0
We get rid of parentheses
2x-2x-8+10=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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