5(x+2)-3=10+7(2x-10)

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Solution for 5(x+2)-3=10+7(2x-10) equation: 



5(x+2)-3=10+7(2x-10)

We move all terms to the left:

5(x+2)-3-(10+7(2x-10))=0

We multiply parentheses

5x-(10+7(2x-10))+10-3=0



We calculate terms in parentheses: -(10+7(2x-10)), so:

10+7(2x-10)

determiningTheFunctionDomain
7(2x-10)+10

We multiply parentheses

14x-70+10

We add all the numbers together, and all the variables

14x-60

Back to the equation:

-(14x-60)



We add all the numbers together, and all the variables

5x-(14x-60)+7=0

We get rid of parentheses

5x-14x+60+7=0

We add all the numbers together, and all the variables

-9x+67=0

We move all terms containing x to the left, all other terms to the right

-9x=-67

x=-67/-9

x=7+4/9

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