5(x+2)-2(3-4x)=3(x+5)-4(4-x)

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Solution for 5(x+2)-2(3-4x)=3(x+5)-4(4-x) equation: 



5(x+2)-2(3-4x)=3(x+5)-4(4-x)

We move all terms to the left:

5(x+2)-2(3-4x)-(3(x+5)-4(4-x))=0

We add all the numbers together, and all the variables

5(x+2)-2(-4x+3)-(3(x+5)-4(-1x+4))=0

We multiply parentheses

5x+8x-(3(x+5)-4(-1x+4))+10-6=0



We calculate terms in parentheses: -(3(x+5)-4(-1x+4)), so:

3(x+5)-4(-1x+4)

We multiply parentheses

3x+4x+15-16

We add all the numbers together, and all the variables

7x-1

Back to the equation:

-(7x-1)



We add all the numbers together, and all the variables

13x-(7x-1)+4=0

We get rid of parentheses

13x-7x+1+4=0

We add all the numbers together, and all the variables

6x+5=0

We move all terms containing x to the left, all other terms to the right

6x=-5

x=-5/6

x=-5/6

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