5(x+2)+6=1-2(3x-2)

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Solution for 5(x+2)+6=1-2(3x-2) equation: 



5(x+2)+6=1-2(3x-2)

We move all terms to the left:

5(x+2)+6-(1-2(3x-2))=0

We multiply parentheses

5x-(1-2(3x-2))+10+6=0



We calculate terms in parentheses: -(1-2(3x-2)), so:

1-2(3x-2)

determiningTheFunctionDomain
-2(3x-2)+1

We multiply parentheses

-6x+4+1

We add all the numbers together, and all the variables

-6x+5

Back to the equation:

-(-6x+5)



We add all the numbers together, and all the variables

5x-(-6x+5)+16=0

We get rid of parentheses

5x+6x-5+16=0

We add all the numbers together, and all the variables

11x+11=0

We move all terms containing x to the left, all other terms to the right

11x=-11

x=-11/11

x=-1

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