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5(x+2)+4=3(x+12)
We move all terms to the left:
5(x+2)+4-(3(x+12))=0
We multiply parentheses
5x-(3(x+12))+10+4=0
We calculate terms in parentheses: -(3(x+12)), so:We add all the numbers together, and all the variables
3(x+12)
We multiply parentheses
3x+36
Back to the equation:
-(3x+36)
5x-(3x+36)+14=0
We get rid of parentheses
5x-3x-36+14=0
We add all the numbers together, and all the variables
2x-22=0
We move all terms containing x to the left, all other terms to the right
2x=22
x=22/2
x=11
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