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5(x+2)+3=3x+2(5+x)
We move all terms to the left:
5(x+2)+3-(3x+2(5+x))=0
We add all the numbers together, and all the variables
5(x+2)-(3x+2(x+5))+3=0
We multiply parentheses
5x-(3x+2(x+5))+10+3=0
We calculate terms in parentheses: -(3x+2(x+5)), so:We add all the numbers together, and all the variables
3x+2(x+5)
We multiply parentheses
3x+2x+10
We add all the numbers together, and all the variables
5x+10
Back to the equation:
-(5x+10)
5x-(5x+10)+13=0
We get rid of parentheses
5x-5x-10+13=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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