5(x+2)+3(2x+1)-(x-5)=10

Solution for 5(x+2)+3(2x+1)-(x-5)=10 equation:

Simplifying
5(x + 2) + 3(2x + 1) + -1(x + -5) = 10

Reorder the terms:
5(2 + x) + 3(2x + 1) + -1(x + -5) = 10
(2 * 5 + x * 5) + 3(2x + 1) + -1(x + -5) = 10
(10 + 5x) + 3(2x + 1) + -1(x + -5) = 10

Reorder the terms:
10 + 5x + 3(1 + 2x) + -1(x + -5) = 10
10 + 5x + (1 * 3 + 2x * 3) + -1(x + -5) = 10
10 + 5x + (3 + 6x) + -1(x + -5) = 10

Reorder the terms:
10 + 5x + 3 + 6x + -1(-5 + x) = 10
10 + 5x + 3 + 6x + (-5 * -1 + x * -1) = 10
10 + 5x + 3 + 6x + (5 + -1x) = 10

Reorder the terms:
10 + 3 + 5 + 5x + 6x + -1x = 10

Combine like terms: 10 + 3 = 13
13 + 5 + 5x + 6x + -1x = 10

Combine like terms: 13 + 5 = 18
18 + 5x + 6x + -1x = 10

Combine like terms: 5x + 6x = 11x
18 + 11x + -1x = 10

Combine like terms: 11x + -1x = 10x
18 + 10x = 10

Solving
18 + 10x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + 10x = 10 + -18

Combine like terms: 18 + -18 = 0
0 + 10x = 10 + -18
10x = 10 + -18

Combine like terms: 10 + -18 = -8
10x = -8

Divide each side by '10'.
x = -0.8

Simplifying
x = -0.8