5(x+2)+2(x-5)=21

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Solution for 5(x+2)+2(x-5)=21 equation: 



5(x+2)+2(x-5)=21

We move all terms to the left:

5(x+2)+2(x-5)-(21)=0

We multiply parentheses

5x+2x+10-10-21=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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