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5(x+1)=95+(x+3)
We move all terms to the left:
5(x+1)-(95+(x+3))=0
We multiply parentheses
5x-(95+(x+3))+5=0
We calculate terms in parentheses: -(95+(x+3)), so:We get rid of parentheses
95+(x+3)
determiningTheFunctionDomain (x+3)+95
We get rid of parentheses
x+3+95
We add all the numbers together, and all the variables
x+98
Back to the equation:
-(x+98)
5x-x-98+5=0
We add all the numbers together, and all the variables
4x-93=0
We move all terms containing x to the left, all other terms to the right
4x=93
x=93/4
x=23+1/4
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