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5(x+1)=90-4(10-x)
We move all terms to the left:
5(x+1)-(90-4(10-x))=0
We add all the numbers together, and all the variables
5(x+1)-(90-4(-1x+10))=0
We multiply parentheses
5x-(90-4(-1x+10))+5=0
We calculate terms in parentheses: -(90-4(-1x+10)), so:We get rid of parentheses
90-4(-1x+10)
determiningTheFunctionDomain -4(-1x+10)+90
We multiply parentheses
4x-40+90
We add all the numbers together, and all the variables
4x+50
Back to the equation:
-(4x+50)
5x-4x-50+5=0
We add all the numbers together, and all the variables
x-45=0
We move all terms containing x to the left, all other terms to the right
x=45
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