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5(x+1)=5(x-1)
We move all terms to the left:
5(x+1)-(5(x-1))=0
We multiply parentheses
5x-(5(x-1))+5=0
We calculate terms in parentheses: -(5(x-1)), so:We get rid of parentheses
5(x-1)
We multiply parentheses
5x-5
Back to the equation:
-(5x-5)
5x-5x+5+5=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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