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5(x+1)=2(2x+5)
We move all terms to the left:
5(x+1)-(2(2x+5))=0
We multiply parentheses
5x-(2(2x+5))+5=0
We calculate terms in parentheses: -(2(2x+5)), so:We get rid of parentheses
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
5x-4x-10+5=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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