5(x+1)-3(x-7)=2(x+4)-3

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Solution for 5(x+1)-3(x-7)=2(x+4)-3 equation: 


Simplifying
5(x + 1) + -3(x + -7) = 2(x + 4) + -3

Reorder the terms:
5(1 + x) + -3(x + -7) = 2(x + 4) + -3
(1 * 5 + x * 5) + -3(x + -7) = 2(x + 4) + -3
(5 + 5x) + -3(x + -7) = 2(x + 4) + -3

Reorder the terms:
5 + 5x + -3(-7 + x) = 2(x + 4) + -3
5 + 5x + (-7 * -3 + x * -3) = 2(x + 4) + -3
5 + 5x + (21 + -3x) = 2(x + 4) + -3

Reorder the terms:
5 + 21 + 5x + -3x = 2(x + 4) + -3

Combine like terms: 5 + 21 = 26
26 + 5x + -3x = 2(x + 4) + -3

Combine like terms: 5x + -3x = 2x
26 + 2x = 2(x + 4) + -3

Reorder the terms:
26 + 2x = 2(4 + x) + -3
26 + 2x = (4 * 2 + x * 2) + -3
26 + 2x = (8 + 2x) + -3

Reorder the terms:
26 + 2x = 8 + -3 + 2x

Combine like terms: 8 + -3 = 5
26 + 2x = 5 + 2x

Add '-2x' to each side of the equation.
26 + 2x + -2x = 5 + 2x + -2x

Combine like terms: 2x + -2x = 0
26 + 0 = 5 + 2x + -2x
26 = 5 + 2x + -2x

Combine like terms: 2x + -2x = 0
26 = 5 + 0
26 = 5

Solving
26 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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