5(x+1)-3(x+4)=7(2-x)

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Solution for 5(x+1)-3(x+4)=7(2-x) equation: 



5(x+1)-3(x+4)=7(2-x)

We move all terms to the left:

5(x+1)-3(x+4)-(7(2-x))=0

We add all the numbers together, and all the variables

5(x+1)-3(x+4)-(7(-1x+2))=0

We multiply parentheses

5x-3x-(7(-1x+2))+5-12=0



We calculate terms in parentheses: -(7(-1x+2)), so:

7(-1x+2)

We multiply parentheses

-7x+14

Back to the equation:

-(-7x+14)



We add all the numbers together, and all the variables

2x-(-7x+14)-7=0

We get rid of parentheses

2x+7x-14-7=0

We add all the numbers together, and all the variables

9x-21=0

We move all terms containing x to the left, all other terms to the right

9x=21

x=21/9

x=2+1/3

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