5(x)+7=(2/3)x+20

Solution for 5(x)+7=(2/3)x+20 equation:

5(x)+7=(2/3)x+20

We move all terms to the left:

5(x)+7-((2/3)x+20)=0


Domain of the equation: 3)x+20)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

5x-((+2/3)x+20)+7=0

We multiply all the terms by the denominator


5x*3)x+20)-((+7*3)x+20)+2=0

We add all the numbers together, and all the variables

5x*3)x+20)-(21x+20)+2=0

Wy multiply elements

15x^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{30}=0$